GeekGold Bonus for All Supporters: 76.25
32.7% of Goal | 28 Days Left
Trying to keep the subject line searchable...
If I am instructed to flip 2 horror (or damage) face up
1) randomly determine 2 cards and then flip those (predetermine the cards)
2) randomly determine 1 card, flip it - follow its instructions which may be to flip facedown again... and repeat possibly allowing me to draw the same card(s)
Draw a random card and flip it. Follow the instructions and then randomly pick a second card (Which may include the first card if the instructions included turn it face down).
follow me on twitter: @zenxacred
I do 1. Well, kind of. I do one at a time (flip then shuffle, flip again), but I don't return the one I just flipped. New ones gained will get added to the shuffle.
Since doing 2 would result in an infinite loop if the condition is flip all (which does happen).
- Last edited Mon Sep 19, 2016 11:56 pm (Total Number of Edits: 1)
- Posted Mon Sep 19, 2016 11:53 pm
New South Wales
Option 2 doesn't work when you have fewer cards than you need to flip. For example, if you were told to flip 3 Horror and only had one, option 2 would have you flip the single card 3 times, which could be horrible. Option 2 also makes no sense with the "flip all your facedown Horror" effect.
Thus, it seems Option 1 is the intended approach. I don't like reshuffling like Zen does, so I just shuffle once and draw the appropriate amount of cards, then flip them.
We have been doing option 1, but when I read the rules over, I don't remember where that choice came from.
2 definitely makes your face down cards more unknown, and flip all doesn't lead to infinite loop, since all isn't a number. It's have 2 flip 3 that gets wonky.
Thank you, I was intending to ask this question.