I am having difficulty in understanding the example on Page 10 of the rules.
Example c1- The Rules state that the player receives 6 VP's. Is this because he has a total of 6 VP's on tucked cards in rows 1 & 2 and 6 BF (4 BF = 1 VP. So 6 x 1? Presumably Row 4 doesn't count as it is not cleared and there are no cards in Row 3.
Example c2- I don't follow why this is 3VP?
Example c4- He has 5 assistant pawns, and 1 VP card. The first 2 assistant pawns don't score, so why is this not 1 x 3 = 3VP? The rules state that this is scored as 6VP.
I am clearly missing something (probably obvious), but would welcome some help please.
I don't have the rules in front of me but hopefully answering c4 will solve the others for you.
Each tucked card add a multiplier to the VP scenario.
In the case of c4 - you will ALWAYS get 1VP get 3+ worker because it is printed on the board. Because the player tucked a card with 1 VP icon on it, he will now score TWO points per 3+ worker, which is why he gets 6VP.
The same goes for the others. Each tucked icon ADDS to the base of 1VP per scenario as a multiplier.
Hopefully this clears things for you!