

I don't have access to rules online as the site doesn't work for some reason and my rulebook is missing.
How exactly do you score green cards? Is it squared, or is it multiplied?
Ex:
Does a set of 3 chop sticks give you 8 points or 9 points?
Also, I'm pretty sure if you have have the whole set (a chop stick, wheel, and a shreddie) you will get 7 additional points. Does this apply only once? (example, if you have 2 of each, will you get additional 14 points?
Thanks.


Pasi Ojala
Finland Tampere
Get the Imperial Assault Campaign module for Vassal from http://www.vassalengine.org/wiki/Module:Star_Wars:_Imperial_Assault
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Square the number of the same symbol separately, then add 7 points for each set of 3 different ones.
If you have two each, you get 4+4+4+7+7 = 26 points.


Robert Stewart
United Kingdom NewcastleuponTyne

If you lay them out as a column each for gearwheel, tablet and dividers, then each column scores the square of its height, and each completed row scores 7 points.


George I.
Switzerland Zurich

And as a math formula: if A, B and C are the available symbols, with 0 ≤ A,B,C ≤ 4, the score is:
A² + B² + C² + 7 * min( A, B, C ) In other words, you square the number of identical symbols and also add 7 points for each complete set of ABC (GearTabletCompass).


Robert Stewart
United Kingdom NewcastleuponTyne

Base game science can go up to 6 of one symbol  Babylon and one of the Guilds each contribute a wild symbol  a "perfect" science game gets you 96 points  6*6 + 4*4 + 4*4 + 4*7 = 36 + 16 + 16 + 28 = 96




BimmyJim wrote: I don't have access to rules online as the site doesn't work for some reason and my rulebook is missing.
How exactly do you score green cards? Is it squared, or is it multiplied?
Ex:
Does a set of 3 chop sticks give you 8 points or 9 points?
Also, I'm pretty sure if you have have the whole set (a chop stick, wheel, and a shreddie) you will get 7 additional points. Does this apply only once? (example, if you have 2 of each, will you get additional 14 points?
Thanks. 3 squared = 9
CCC = 9
Yes, 2 separate sets of 3 different gives you +14 for a total of 31
C C C = 9 B B = 4 A A = 4 7 7




yeah, i'm no whiz with the math either… get the app. Actually really well done, with tons of extras and an amazing reference guide.
https://itunes.apple.com/us/app/7wonderscompanion/id504797...
check it out!


Nikolai
Germany Münster
Hidden trackable information in games sucks!
I play games for fun and pursuing the goal to win the game is fun! :)

Picon wrote: And as a math formula: if A, B and C are the available symbols, with 0 ≤ A,B,C ≤ 4, the score is: A² + B² + C² + 7 * min( A, B, C )
The ≤ 4 restriction is unnecessary, the formula is correct for all A,B,C ≥ 0. In base game alone the number of same symbols can go as high as 6 (as rmsgrey has already pointed out) and with all current expansions, the maximum is as high as 11 for one symbol and 5 for both others (and I suppose the Babylon expansion will raise these values further). Although these extremes would be almost impossible to pull off in practice, more than 6 of a kind can realistically happen with expansions.


Gregory Mucklow
United Kingdom Swindon

BimmyJim wrote: a chop stick, wheel, and a shreddie
Haha!! Love this!


George I.
Switzerland Zurich

Darador wrote: The ≤ 4 restriction is unnecessary, the formula is correct for all A,B,C ≥ 0. Correct, of course. The ≤ 4 "restriction" was imposed for educational purposes. The same formula, of course, applies for any number.


Nikolai
Germany Münster
Hidden trackable information in games sucks!
I play games for fun and pursuing the goal to win the game is fun! :)

Picon wrote: Correct, of course.
I admit I was probably nitpicking...


M S
United States New York

if it helps, I made an excel sheet and uploaded it to BGG :)
http://boardgamegeek.com/filepage/87421/7wondersautoscore...



