The Sideslip maneuver forced by an S, or SS result on the corner straining
chart and the sideslip maneuver caused by a blocking chariot are all
the same. Correct?
The diagram in 6.73 shows a sideslip to the inside. But S or SS cause
sideslips to the outside. If a horse team is in the square where the
arrowhead is in the diagram, and if the chariot sideslips to the
outside, the the horse team would end up where the car is located
in the diagram. Note, I realize you can't sideslip if another
chariot is in the way, just assume the other chariot is not
there, but use it's drawing as a reference. Do I have that correct?
A sideslip to the outside in the diagram would be slightly
backwards as well?
Yes, you are correct. The sideslip must be to an adjacent square which is totally beside the occupied square or partially behind it. So in your example you will move slightly backwards. If your team is on a parallel corner square you would slide sideways with no backwards movement. See page 4 for an example of a parallel square.