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Burgle Bros.» Forums » Rules

Subject: Fort Knox setup rss

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Chris Clarke
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Am I daft or is the third safe not mentioned?
 
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Ponsonby Britt, OBE
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You set aside two safes, shuffle the remaining floor tiles, and split them into two piles for the two floors. Now take the two held safes and add one to each pile. At this point, one pile (one floor) will now have two safes in it. Thus the statement when it comes to safecracking, "each safe [will have] 7 or 8 numbers in the combination."

Hope this makes sense.
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Chris Clarke
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Lol. Right. You shuffle ALL the rest of the tiles. Won't one of the two floors now have two staircases, too? That's cool.
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Garry Rice
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Played this setup tonight and the second floor was absolutely brutal. The second floor naturally had two safes (although they did share the same column), but we chose to take out the center tile...that natural loop just became brutal at the end as the guard was constantly going around the loop and crossing the safe just about every other turn...we wound up losing after cracking two safes and getting 2 dice on the final safe...shake

It would probably have been advisable to try taking a different tile the first time we attempted this (or to make sure two safes were on the first floor).
 
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Lutz Pietschker
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ponsonbybritt wrote:
Thus the statement when it comes to safecracking, "each safe [will have] 7 or 8 numbers in the combination."
I think that statement refers to the fact that one of the 8 key tiles may be the empty tile spot.
 
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Juan C. Suárez
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There could even be 6 key tiles, if the empty tile and two of the safes share same row/column.
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