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The Kids of Catan» Forums » General

Subject: Tactical variant for older children rss

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Eric Pelzer
United States
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Here is a more tactical variant of the rules, that I use when playing with my older child :

Each player takes his turn, in clockwise order :

1/ the current player decides how far he wants to rotate the gameboard : 1, 2 or 3 steps

2/ he rotates the gameboard clockwise accordingly

3/ everyone takes the resource (if missing in his cart) from the spot closest to his pawn, and puts it where he wants in his cart

4/ those who have 3 different resources in their cart get as many points as there are red-roofed buildings still to be placed in the village (so 12 points the first time), then they place a building in the village and dispatch the resources of their cart on empty spots

5/ if the current player lands deliberately next to the robber, then he can steal one of his missing ressource from the back of the cart of another player, but any other player who has landed next to the robber loses one resource that he must place on an empty spot

The game ends when everyone has placed all his buildings.

Then everyone sums up how many points he has received during the game, and the winner is the one who's got the more points. In case of equality, the winner is the first one who placed a building.

 
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Martin Matt
Portugal
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eric.pelzer wrote:


4/ those who have 3 different resources in their cart get as many points as there are red-roofed buildings still to be placed in the village (so 12 points the first time)[...]
In case of equality, the winner is the first one who placed a building.



Using this variant, the critical phase occurs early in the game and this could lead to a lost of interest when a few (and occasionally "not so few") buildings are still to be placed since the winner could already be known even the later has placed less buildings than the former. Furthermore, it seems unfair in some situations.

Let me present some examples of 2-player games(for sake of simplicity) to illustrate the point (A and B refer to players):

Ex1:
Sequence of building: A-B-A-B-A-B-A-B-B-?-?-?
By now:
player A (4 buildings in the village) = 36 pts (advantage)
player B (5 buildings in the village) = 36 pts

There are still 3 buildings to place in the village and B has to build the 10th or the game is decided in favour of player A, regardless B has built more buildings than A by now and regardless B places the 11th and 12th buildings, totalling 7 buildings (against 5).

Ex2:
Sequence of building: A-A-B-A-B-A-?-?-?-?-?-?
By now:
player A (4 buildings in the village) = 39 pts (winner)
player B (2 buildings in the village) = 24 pts

Note that even player B places in the village the remaining 6 buildings, totalling 8 (against 4), player A is the winner.


 
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