Shooting for the lowest total, one plays plays 5 and 1, the other player plays 3. The first player plays Sleeping Beauty to "cancel the sum of one adventurer card" to eliminate the 5 and reduce to a sum of 1. The second player plays Shrinking Potion and reduces to a sum of 1. The tiebreaker goes to the player who played the strength card with the highest strength number -- is the first player's 5 still considered "played", even though it's value was canceled, so that it wins the tiebreaker?
Bonus question -- if a card from Expansion 1 also showing paws or a coin (4 & 5) is put to sleep with Sleeping Beauty, does the player still collect the bonus in a later phase?
1. The player who played the 5 would win the tiebreaker.
The tiebreaker text says;
"In case of a tie for the highest and/or lowest total, the tied player who played the card with the highest strength number wins the tie and captures the treasure."
I bolded "played" because it's important to note when sleeping beauty is played it doesn't remove the card from being in play, it just cancels the sum.
Sleeping Beauty: "The player cancels the sum of one adventurer card they have played"
So all you are doing is canceling the sum of the card, not the fact that the card was still played.
Bonus question I have no insight since I do not own the expansion.