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Subject: What’s the Minimum Number of Remaining Hazards? rss

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Mark James Schryver
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Pulaski
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Upon completion of the Red Phase, what’s the minimum number of remaining Hazard cards?

I know that – from a strictly mathematical standpoint – the answer is three.

But I’ve played over a thousand games at this point, and never gotten below four.

Is there any way to answer this question, short of writing a computer program to run every combination of shuffles and draws?

Thanks,
Mark
 
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Dave Moser
United States
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I feel certain the answer is 3. I don’t feel like going to the bother right now, but I’m sure if I laid out the cards in front of me and could choose every hazard and fighting card, I could easily defeat every hazard for three rounds. Match up the ones and minus ones to take zero cards, etc. Grab every destroy card and use those to remove bad cards without losing battles.

Next time I have the game out I’ll give it a try, but I’d wager a bundle that it’s possible.
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Mark James Schryver
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If you come up with a path that works, please let us know the details!
 
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