Ken Thibodeau
Canada Quebec Quebec

According to the German/English translation file posted by Otakugirly, Baronesses cards read: "At game end receive 3 PP. If you have 2 Baronesa cards receive 4 PP each, if you have 3 receive 5 PP each." (my underlining)
The way it is written, it sounds like you will earn 3, 8 or 15 PP at game end. However, when I read the Alea English cards, I understand I should earn 3, 4 or 5 PP at game end if I have activated 1, 2 or 3 Baronesses. So which interpretation is right?

Steve K
United Kingdom
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I don't understand why you've interpreted the English cards as you have.
My official English card (Baronesa Um) says:
Quote: At game end, score 3PP. If you have 2 or 3 activated Baronesses, score 4 or 5 PP each.
Surely this matches Otakugirly's wording? If you have all 3 Baronneses  each of them earns 5PP, so you get a total of 15PP.

John Earles
Canada Toronto Ontario

I agree with Steve.
The RGG Baronesa cards are clear to me. You score 3 PP, 8PP, or 15PP for 1, 2, or 3 activated Baronesa cards at Game End.

Ken Thibodeau
Canada Quebec Quebec

SteveK2 wrote: I don't understand why you've interpreted the English cards as you have. My official English card (Baronesa Um) says: Quote: At game end, score 3PP. If you have 2 or 3 activated Baronesses, score 4 or 5 PP each. Surely this matches Otakugirly's wording? If you have all 3 Baronneses  each of them earns 5PP, so you get a total of 15PP.
Wow I didn't see the last word (each) at the end of the sentence on the card. I went from memory for asking the question but it is indeed perfectly clear. Sorry for the poor reading ability. I had the feeling the Baronesses were a bit underpowered Now they're not!! Last night I won by a 3point margin but now I realize I will have to concede victory to my girlfriend who had 2 baronesses...

Mik Svellov
Denmark Copenhagen N EU

Just make sure nobody gets more than one Baroness  and certainly not all three!

Raúl Lopezosa
Spain Almendralejo Badajoz

Baronesses cards read: "At game end receive 3 PP. If you have 2 Baronesa cards receive 4 PP each, if you have 3 receive 5 PP each."
So, if you have 1 Baronesses you get 3 PP.
So, if you have 2 Baronesses, for Baronesses A you get 3 PP + (4 x 2)PP = 11PP (The if condition that gives lots of point is independent from the 3 first point). And the Baronesses B gives other 11 PP.
So, if you have 3 Baronesses.....

Ken Thibodeau
Canada Quebec Quebec

csibadajoz wrote: Baronesses cards read: "At game end receive 3 PP. If you have 2 Baronesa cards receive 4 PP each, if you have 3 receive 5 PP each."
So, if you have 1 Baronesses you get 3 PP.
So, if you have 2 Baronesses, for Baronesses A you get 3 PP + (4 x 2)PP = 11PP (The if condition that gives lots of point is independent from the 3 first point). And the Baronesses B gives other 11 PP.
So, if you have 3 Baronesses.....
No, I don't think this is right

Dan Schaeffer
United States Unspecified Illinois

csibadajoz wrote: Baronesses cards read: "At game end receive 3 PP. If you have 2 Baronesa cards receive 4 PP each, if you have 3 receive 5 PP each."
So, if you have 1 Baronesses you get 3 PP.
So, if you have 2 Baronesses, for Baronesses A you get 3 PP + (4 x 2)PP = 11PP (The if condition that gives lots of point is independent from the 3 first point). And the Baronesses B gives other 11 PP.
So, if you have 3 Baronesses.....
No, it's not an additional 4 or 5 PP, it changes the 3 to 4 or 5 depending on how many you get.
1 Baroness = 3 PP 2 Baronesses = 8 PP 3 Baronesses = 15 PP
Those scores for multiples are already pretty big; adding another 3 PP because the sentences are "independent" is unnecessary and illogical. If that's what the designer had intended, adding the word "also" would have made it crystal clear. Unless I see an official response otherwise, I'm going to assume that the 4/5 PP for multiples is instead of the 3 PP for a single.

Raúl Lopezosa
Spain Almendralejo Badajoz

Really, I am not sure about I said yestarday, but I am not sure neither about your replies....
Is there any official answer about that?

Ken Thibodeau
Canada Quebec Quebec

User Great Dane's reply (see above post) is pretty official as he was a playtester. I assume that if the interpretation of the rule mentionned above his post wasn't true, he would've corrected it

Andrew Swan
Australia Randwick NSW

csibadajoz wrote: Baronesses cards read: "At game end receive 3 PP. If you have 2 Baronesa cards receive 4 PP each, if you have 3 receive 5 PP each."
So, if you have 1 Baronesses you get 3 PP.
So, if you have 2 Baronesses, for Baronesses A you get 3 PP + (4 x 2)PP = 11PP (The if condition that gives lots of point is independent from the 3 first point). And the Baronesses B gives other 11 PP.
So, if you have 3 Baronesses..... I can see how you would think that, and I agree it's poorly written in the English version at least. However the intent of the card seems to be simply that each Baroness is worth 3/4/5 depending on whether you have 1/2/3 of them.
Let's just hope no M:tG players play this game.


