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Subject: Air Attack Procedure rss

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Luke Freck
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Hello all, I'm just starting to learn this game hopefully someone can clear something up. I am hoping sometime in the future that Fusag can make a Boot Camp session for the major mechanics of this game when time allows him to do so.

So on to the question. In the rule book (I do have the errata from Fire and Movement), on page 9 it is talking about the Air Attack Tables. The Air Attack Procedure states:
Quote:
1.Add up the attack values of all units - of all types - in the strike. (Remember, this includes half - rounded to the nearest whole number - of the air units lost to A.A. fire.)

2. If both torpedo and dive bombers are participating...it's a "coordinated" attack...in July '42 add 1/4 for every step of attack planes (of either type).

In the example of air strike resolution it states that there are 4 SBD steps and 2 TBF's. The 4 SBD steps have an attack value of 3.

The attack value of a SBD is 6 when I look at the counter. Where does it get the 3 from? I have checked and I'm wondering if that was a typo.

So in scenario 1 we have, just for the first strike: 8 SBDs, 4 F4Fs and, 2 TBDs. I understand we do not add escorts (F4Fs even their attack value is 0). Would that be 56 for attack value assuming no losses to CAP? SBD=6, TBD=4, F4F=0

If we have a "coordinated" is there a easier way of calculating the DRM for what time frame we are in?

For instance: If we are in Jan-Jul '42 and we add 1/4 for every step of attack planes (of either type). How do we add that to say 6 SBDs and 2 TBDs as an example?
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James Fung
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Mroo7 wrote:
The attack value of a SBD is 6 when I look at the counter. Where does it get the 3 from? I have checked and I'm wondering if that was a typo.

Bad counter design. The full side of a counter represents 2 air steps (a whole air point), and the back side represents 1 air step (half an air point). I believe at point both Japanese and US sides used air points, but for some reason the US got changed to air steps.

Quote:
For instance: If we are in Jan-Jul '42 and we add 1/4 for every step of attack planes (of either type).

That's 1/4 air strength, not a step, for every step of attack planes.
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Luke Freck
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Thanks for responding James.

So in scenario 1 to calculate the attack values we have, 8 SBDs and 4 TBDs for just the first strike. I understand we do not add escorts (F4Fs even their attack value is 0). Would that be 56 for attack value assuming no losses to CAP?

Could you explain the "coordinated" modifiers for adding steps? For instance; in Jul '42 it is to add 1/4 for every step of attack planes (of either type). Does that mean if you have 3 TBDs and 1 SBD, you would get a total of 1 step. You can then choose that you want 1 extra SBD to join OR you get 1 extra TBD and 1 extra SBD?
 
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James Fung
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Mroo7 wrote:
So in scenario 1 to calculate the attack values we have, 8 SBDs and 4 TBDs for just the first strike. I understand we do not add escorts (F4Fs even their attack value is 0). Would that be 56 for attack value assuming no losses to CAP?

3 per SBD, 1 per TBD, 0 per F4F, so 28 before the coordinated bonus.

Quote:
Could you explain the "coordinated" modifiers for adding steps? For instance; in Jul '42 it is to add 1/4 for every step of attack planes (of either type). Does that mean if you have 3 TBDs and 1 SBD, you would get a total of 1 step. You can then choose that you want 1 extra SBD to join OR you get 1 extra TBD and 1 extra SBD?

Sorry, I read too fast. I'll edit my previous post. It's not a step bonus, it's an air strength bonus. Each step gives you a 0.25 (or 0.5) air strength.
 
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Bertrand Guillou-Keredan
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Another question :
- 2 X SDB units ( value 6) are respectively in the "1 Hit" and the "2 Hits" boxes. For calculating air attack, the two SDB Units have an attack value of 3 (Halved). And after the Attack, the first is inverted and the second removed.
Does this seem correct?
 
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James Fung
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BertGK wrote:
Another question :
- 2 X SDB units ( value 6) are respectively in the "1 Hit" and the "2 Hits" boxes. For calculating air attack, the two SDB Units have an attack value of 3 (Halved). And after the Attack, the first is inverted and the second removed.
Does this seem correct?

The way I play it is this: you have 4 SBD steps, 3 of which are hit. During the air attack, you effectively have 4 - 1.5 = 2.5 SBD steps = 7.5 air strength. After the attack, you have only 1 step left, which is one SBD counter on its back side.
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Bertrand Guillou-Keredan
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all clear now !

Thank you
 
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