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Subject: How much to pay for dice if you buy from several other players rss

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Morten K
Denmark
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During a game yesterday we couldn't quite figure out how much to pay when buying a die from two different players to go with one of our own.

Would it be 2 deniers to each? Or 4 deniers to the first and 6 to the second player? Or something completely different?
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Poland
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It's all depends how many dices you will use to do your action. That is the base for calculating a dice price.
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Poland
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In other words if you only use those two dices both of them should get 4 deniers each but if you use also one from your pool they get 6 denires each.
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Dawid
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You always pay the same price for each die that you buy.
Whether it is 2, 4 or 6 for each die you acquire depends only on how many dice you are going to use during current action and does not depend on where this dice come from.

In your example, you want to use 3 dice so you pay 6 for each one you buy.
So it is 6 for both players (sum of 12).
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Kris Ardianto
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DKI Jakarta - Jakarta Utara
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When buying dice, you use the price set based on how many dice you use of the action intended.
So if you buy a die to go with a group of a single die, you buy it for 2 deniers.
But if you buy a dice to go with a group of two dice, you buy it for 4 deniers each.
And if you buy a die to go with a group of three dice (max), you buy it for 6 deniers each.
It gets way more expensive when you use larger group.
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Wayne Shepherdson
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Tigrillo wrote:
During a game yesterday we couldn't quite figure out how much to pay when buying a die from two different players to go with one of our own.

Would it be 2 deniers to each? Or 4 deniers to the first and 6 to the second player? Or something completely different?
Like what the others said, Maybe this would simplify it.

The costs is 2 for 1 dice, 4 for set of 2, 6 for set of 3.

Since in your example, you are making a set of 3 dice, you pay 6 to each of your opponents.
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Jarek Szczepanik
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Generally, the others are right. Let me give a few examples though:

A) You want to use only one die which you buy from another player (including the neutral player) -> that will cost you 2 deniers (because you're using only one die for an action)

B) You want to use two dice in total. One is yours, the other one is bought from neutral player (or any other player) - you pay 4 deniers to the player which you buy a due from (because you're using 2 dice for an action)

C) You want to use 2 dice, and both of them come from player 3. You must pay 4 deniers per die = 8 deniers to player 3

D) You want to use 3 dice to perform an action. One is yours and you purchase the other two from neutral player and player 2 respectively. You have to pay 6 deniers per die (because you're using 3 dice) - 6 to the neutral player and 6 to the player 2.

Hope that helps.
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Morten K
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Thank you all!
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